Löse die folgenden linearen Gleichungen a(bx + c) = d(ex + f)

3 (-10x + 90) = 6 (2x + 10)
 x = 5
-8 (4x + 2) = 8 (10x - 114)
 x = 8
-4 (5x - 170) = 5 (10x + 10)
 x = 9
4 (4x + 9) = 7 (9x + 32)
 x = -4
8 (4x + 8) = 8 (-3x + 78)
 x = 10
-4 (-8x + 8) = 4 (10x - 16)
 x = 4
4 (10x + 3) = 4 (-5x - 42)
 x = -3
3 (8x + 4) = 6 (6x - 14)
 x = 8
7 (9x + 3) = -2 (7x - 203)
 x = 5
2 (10x + 3) = (-6x + 6)
 x = 0
6 (6x + 6) = 4 (x - 23)
 x = -4
6 (10x + 8) = 3 (-5x + 91)
 x = 3
(7x - 28) = (10x + 2)
 x = -10
-5 (6x + 4) = (3x - 185)
 x = 5
-(-10x - 299) = -3 (10x + 7)
 x = -8
4 (9x + 4) = -2 (8x - 34)
 x = 1
5 (9x + 5) = 5 (2x + 19)
 x = 2
6 (7x + 7) = 7 (5x - 2)
 x = -8
(4x - 366) = -9 (8x - 10)
 x = 6
5 (-2x - 18) = 10 (5x + 9)
 x = -3