Löse die folgenden linearen Gleichungen a(bx + c) = d(ex + f)

-10 (5x - 6) = -4 (4x + 2)
 x = 2
-(-9x - 35) = 5 (10x + 7)
 x = 0
9 (-6x + 5) = 3 (10x + 183)
 x = -6
8 (5x + 0) = 8 (8x - 6)
 x = 2
10 (6x - 4) = -10 (-x - 1)
 x = 1
4 (6x - 7) = 4 (3x + 11)
 x = 6
-2 (9x + 9) = -9 (x + 7)
 x = 5
-6 (10x + 115) = 3 (9x + 2)
 x = -8
4 (-7x + 89) = 9 (3x + 9)
 x = 5
-10 (7x + 9) = 5 (-5x - 90)
 x = 8
-5 (6x + 75) = 7 (2x + 3)
 x = -9
(3x + 396) = 9 (5x + 2)
 x = 9
2 (9x - 4) = 2 (6x + 2)
 x = 2
8 (-10x + 5) = 4 (2x - 166)
 x = 8
9 (7x + 8) = (6x + 243)
 x = 3
-4 (10x - 151) = -4 (-5x - 1)
 x = 10
5 (4x + 16) = 10 (-7x + 8)
 x = 0
3 (4x + 112) = 8 (9x - 3)
 x = 6
-9 (9x - 10) = 10 (10x + 9)
 x = 0
2 (4x - 176) = -8 (9x + 4)
 x = 4