Löse die folgenden linearen Gleichungen a(bx + c) = d(ex + f)

2 (7x + 3) = 3 (5x + 0)
 x = 6
6 (-7x + 8) = 6 (9x - 40)
 x = 3
(9x - 5) = -7 (x + 3)
 x = -1
10 (3x + 4) = 5 (6x + 8)
 x = 8
2 (4x + 6) = 2 (3x + 6)
 x = 0
(-x + 20) = -5 (7x - 4)
 x = 0
-4 (9x - 111) = 8 (2x + 10)
 x = 7
9 (10x - 59) = 3 (8x - 1)
 x = 8
8 (5x - 35) = -5 (2x + 6)
 x = 5
-(8x + 89) = 3 (6x + 5)
 x = -4
(10x + 3) = (2x + 3)
 x = 0
10 (8x - 106) = 4 (-7x + 5)
 x = 10
2 (10x - 25) = -6 (x + 4)
 x = 1
(3x + 104) = 5 (3x + 4)
 x = 7
(8x + 23) = (10x + 5)
 x = 9
(8x - 450) = 6 (-8x + 9)
 x = 9
5 (5x + 5) = 2 (8x - 10)
 x = -5
8 (3x + 4) = 8 (7x + 20)
 x = -4
(4x - 8) = -4 (4x - 8)
 x = 2
-4 (7x + 10) = 4 (9x + 54)
 x = -4