Löse die folgenden linearen Gleichungen a(bx + c) = d(ex + f)

(6x - 14) = 8 (-6x + 5)
 x = 1
-10 (3x - 36) = 10 (2x + 1)
 x = 7
9 (8x - 52) = 9 (2x + 8)
 x = 10
2 (7x - 1) = (10x - 2)
 x = 0
10 (x + 3) = (-2x + 30)
 x = 0
10 (6x - 28) = 10 (-3x + 8)
 x = 4
2 (9x - 30) = -(4x - 6)
 x = 3
7 (-9x + 25) = -7 (-7x - 9)
 x = 1
7 (9x - 1) = (-6x + 338)
 x = 5
-3 (2x + 10) = 4 (8x - 74)
 x = 7
4 (-10x + 4) = 2 (-7x - 83)
 x = 7
3 (x + 6) = 7 (5x - 2)
 x = 1
4 (9x + 2) = 4 (2x + 51)
 x = 7
7 (9x + 8) = 4 (7x + 49)
 x = 4
6 (10x + 5) = -10 (-5x - 10)
 x = 7
(-5x + 290) = 10 (2x + 4)
 x = 10
4 (x + 9) = 4 (2x + 8)
 x = 1
3 (-6x + 90) = 2 (10x + 2)
 x = 7
(6x - 14) = (-9x + 1)
 x = 1
10 (2x + 2) = (9x + 119)
 x = 9