Löse die folgenden linearen Gleichungen a(bx + c) = d(ex + f)

4 (4x - 3) = (5x + 65)
 x = 7
9 (3x + 1) = -3 (8x - 71)
 x = 4
8 (6x + 14) = 8 (7x + 6)
 x = 8
3 (4x + 1) = 3 (2x + 7)
 x = 3
4 (4x - 8) = (2x - 4)
 x = 2
5 (-3x + 27) = 7 (4x + 7)
 x = 2
4 (-2x - 6) = 8 (6x - 52)
 x = 7
10 (4x - 15) = 5 (-10x + 6)
 x = 2
3 (2x + 20) = 6 (x + 10)
 x = 0
(2x - 81) = -7 (3x + 5)
 x = 2
-6 (-x + 4) = 2 (7x - 52)
 x = 10
-10 (3x + 10) = -5 (4x + 4)
 x = -8
3 (2x - 278) = -10 (8x + 6)
 x = 9
(2x + 1) = -(-5x - 1)
 x = 0
10 (9x + 9) = 9 (10x + 10)
 x = 7
4 (3x + 7) = 2 (-6x + 74)
 x = 5
3 (-5x + 1) = -(10x + 2)
 x = 1
(5x - 55) = 7 (5x + 5)
 x = -3
2 (4x + 3) = -10 (-3x + 17)
 x = 8
-4 (6x - 77) = 2 (4x + 10)
 x = 9