Löse die folgenden linearen Gleichungen a(bx + c) = d(ex + f)

-4 (6x - 9) = 6 (7x - 27)
 x = 3
4 (3x - 52) = 8 (-2x + 2)
 x = 8
(4x - 14) = 10 (x - 5)
 x = 6
(10x + 276) = 9 (8x + 10)
 x = 3
(9x + 144) = 9 (5x + 4)
 x = 3
-4 (-4x + 12) = 3 (9x - 5)
 x = -3
(x + 107) = 9 (10x + 2)
 x = 1
-2 (3x + 1) = 2 (6x - 91)
 x = 10
-6 (4x - 1) = 2 (7x - 187)
 x = 10
2 (6x - 4) = 4 (2x + 4)
 x = 6
-3 (x + 2) = (3x - 66)
 x = 10
4 (6x - 6) = -8 (5x - 5)
 x = 1
6 (6x - 17) = 6 (-7x - 4)
 x = 1
8 (4x - 4) = -(-10x - 34)
 x = 3
9 (-6x + 38) = 6 (x + 7)
 x = 5
6 (4x + 8) = 9 (9x - 58)
 x = 10
2 (6x - 9) = -6 (-8x + 3)
 x = 0
2 (9x - 98) = -10 (3x + 10)
 x = 2
4 (4x + 16) = 8 (9x + 1)
 x = 1
-3 (2x + 121) = -9 (9x + 7)
 x = 4