Löse die folgenden linearen Gleichungen a(bx + c) = d(ex + f)

9 (6x - 29) = -3 (-2x + 7)
 x = 5
10 (7x + 3) = -(5x - 180)
 x = 2
-8 (-3x + 4) = 4 (-6x - 92)
 x = -7
8 (5x - 1) = 2 (6x + 10)
 x = 1
2 (3x - 3) = -3 (6x + 2)
 x = 0
7 (6x - 24) = 8 (2x + 5)
 x = 8
2 (x - 27) = 2 (-10x + 6)
 x = 3
2 (-6x + 42) = 3 (5x + 10)
 x = 2
3 (2x + 33) = 3 (5x + 6)
 x = 9
7 (4x + 8) = 2 (6x + 36)
 x = 1
9 (2x - 2) = 9 (5x + 1)
 x = -1
6 (-2x - 3) = -3 (9x + 41)
 x = -7
(7x + 1) = 8 (x + 1)
 x = -7
3 (5x + 6) = 3 (9x - 26)
 x = 8
3 (8x + 6) = (x + 202)
 x = 8
-3 (3x - 58) = 4 (3x - 9)
 x = 10
4 (-4x - 62) = 8 (8x - 1)
 x = -3
5 (-5x + 94) = 5 (9x + 10)
 x = 6
6 (9x - 7) = -4 (9x - 57)
 x = 3
3 (9x - 7) = (7x - 81)
 x = -3