Löse die folgenden linearen Gleichungen a(bx + c) = d(ex + f)

5 (6x + 18) = 5 (9x + 9)
 x = 3
9 (x + 29) = 7 (6x + 9)
 x = 6
8 (2x + 6) = 6 (-4x + 8)
 x = 0
6 (6x - 1) = 6 (4x + 1)
 x = 1
6 (-10x - 6) = 3 (3x - 173)
 x = 7
-2 (5x + 10) = 5 (8x - 4)
 x = 0
8 (10x + 5) = 2 (6x - 48)
 x = -2
-3 (6x - 390) = -9 (-10x - 10)
 x = 10
3 (4x - 102) = 3 (-7x + 8)
 x = 10
-6 (x - 1) = 6 (9x - 99)
 x = 10
-9 (8x + 10) = 6 (x - 145)
 x = 10
(9x + 477) = 7 (8x + 1)
 x = 10
(7x + 56) = 9 (5x + 2)
 x = 1
3 (4x - 69) = -3 (4x + 5)
 x = 8
(9x + 513) = -9 (10x + 9)
 x = -6
(8x + 1) = (10x + 3)
 x = -1
3 (8x + 86) = 10 (9x + 6)
 x = 3
-10 (7x + 2) = (x - 588)
 x = 8
4 (6x + 19) = 4 (9x + 7)
 x = 4
-3 (8x - 8) = -8 (3x - 3)
 x = 6